Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A bulet of mass m and velocity v strikes a mass M connected to a spring (k=spring constant) [the spring is placed horizontaly and other end is fixed.]and get embeded to it . Find the amplitude of oscilation.
first applying conservation of momentam mv = (M+m)Vf Vf = mv/m+M now , kinetic energy of block + mass = KE KE = (m+M)Vf2 /2 this system will stop moving when its all KE is converted into PE so , KE = PE KX2 = (M+m)Vf2 X =[ m2v2 /(M+m)K ]1/2 = max amplitude
first applying conservation of momentam
mv = (M+m)Vf
Vf = mv/m+M
now , kinetic energy of block + mass = KE
KE = (m+M)Vf2 /2
this system will stop moving when its all KE is converted into PE
so , KE = PE
KX2 = (M+m)Vf2
X =[ m2v2 /(M+m)K ]1/2 = max amplitude
please approve my answers if they are correct
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -