Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
A bulet of mass m and velocity v strikes a mass M connected to a spring (k=spring constant) [the spring is placed horizontaly and other end is fixed.]and get embeded to it . Find the amplitude of oscilation.
first applying conservation of momentam
mv = (M+m)Vf
Vf = mv/m+M
now , kinetic energy of block + mass = KE
KE = (m+M)Vf2 /2
this system will stop moving when its all KE is converted into PE
so , KE = PE
KX2 = (M+m)Vf2
X =[ m2v2 /(M+m)K ]1/2 = max amplitude
please approve my answers if they are correct
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !