A simple pendulum of length l and mass m is suspended in a car that is moving with constant velocity v around a circle of radius r. Find its time period and equilibrium position?pls post fast

car is moving along the circle so centripital force is acting on the car but bob experiences a centrifugal force ....

let the angle made with verticle is @ & T is the tension in the string  then

Tcos@ = mg

Tsin@ = mv²/r

tan@ = v²/rg  

bob is at equilibrium at @ = tan^-1 (v²/g)

now

       net force acting on bob = (mv²r) i + (mg) j

                                    a = v²/r i+ g j

               magnitude of a= [ (v²/r)² + g² ]

T = 2pi(L/g_eff)

  =2pi { L/[(v²/r)² +g²] }^1/2

Approved