string qu

Question

STRING IS TIED B/W POINTS X=0 AND X=L IT VIBRATES IN FUNDAMENTAL MODE .MASS PER UNIT LENGTH IS GIVEN TO BE μ.TENSION IN THE STRING IS T AND AMPLITUDE IS A. FIND THE ENERGY OF THE STRING.

ANS--A²TΠ²/4L

SAGAR SINGH - IIT DELHI · Accepted Answer

Dear student You have to integrate 1/2uxdx/L from 0 to A You will get the answer A2uA2/4L Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation. All the best. Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian. Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar.. Askiitians Expert Sagar Singh B.Tech, IIT Delhi

Wave Motion> string qu...

STRING IS TIED B/W POINTS X=0 AND X=L IT VIBRATES IN FUNDAMENTAL MODE .MASS PER UNIT LENGTH IS GIVEN TO BE μ.TENSION IN THE STRING IS T AND AMPLITUDE IS A. FIND THE ENERGY OF THE STRING.

ANS--A²TΠ²/4L

iitian shukla , 14 Years ago

SAGAR SINGH - IIT DELHI

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A particle on a speing executes shm when the particle is found at x=xmax/2 the speed of the partcle is
A)vx=vmax
B)vx=√3vmax/2
C)vx=√2vmax/2
D)vx=vmax/2

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Wave Motion> string qu...

STRING IS TIED B/W POINTS X=0 AND X=L IT VIBRATES IN FUNDAMENTAL MODE .MASS PER UNIT LENGTH IS GIVEN TO BE μ.TENSION IN THE STRING IS T AND AMPLITUDE IS A. FIND THE ENERGY OF THE STRING. ANS--A2TΠ2/4L

iitian shukla , 14 Years ago

SAGAR SINGH - IIT DELHI

LIVE ONLINE CLASSES

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A particle on a speing executes shm when the particle is found at x=xmax/2 the speed of the partcle is A)vx=vmax B)vx=√3vmax/2C)vx=√2vmax/2D)vx=vmax/2

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STRING IS TIED B/W POINTS X=0 AND X=L IT VIBRATES IN FUNDAMENTAL MODE .MASS PER UNIT LENGTH IS GIVEN TO BE μ.TENSION IN THE STRING IS T AND AMPLITUDE IS A. FIND THE ENERGY OF THE STRING.

ANS--A²TΠ²/4L

A particle on a speing executes shm when the particle is found at x=xmax/2 the speed of the partcle is
A)vx=vmax
B)vx=√3vmax/2
C)vx=√2vmax/2
D)vx=vmax/2