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Grade: 11
        

 



A particle executes simple harmonic motion with an amplitude of 10 cm. At what distance from the mean position are the kinetic and potential energies equal ?


 

7 years ago

Answers : (1)

vikas askiitian expert
509 Points
							

A = 10cm =0.1m

kinetic energy = mA2w2 cos2wt/2 ................1

potential energy = mA2w2sin2wt/2 ..................2

PE = KE           (GIVEN)

so

       tanwt = 1

      sinwt =1/sqrt(2)

now ,  x = Asinwt

            =A/sqrt2= 7cm

7 years ago
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