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A particle executes simple harmonic motion with an amplitude of 10 cm. At what distance from the mean position are the kinetic and potential energies equal ?

 



A particle executes simple harmonic motion with an amplitude of 10 cm. At what distance from the mean position are the kinetic and potential energies equal ?


 

Grade:11

1 Answers

vikas askiitian expert
509 Points
10 years ago

A = 10cm =0.1m

kinetic energy = mA2w2 cos2wt/2 ................1

potential energy = mA2w2sin2wt/2 ..................2

PE = KE           (GIVEN)

so

       tanwt = 1

      sinwt =1/sqrt(2)

now ,  x = Asinwt

            =A/sqrt2= 7cm

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