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a particle executin shm covers a distance x in first second from its mean position and it covers distance y in another one second. find amplitude of the particle
Dear aabhas ,
the genreal equation of shm is x(t) = Asin(wt)
so just plug in the values given in the quesiton and solve ....x
x = A sinw ------(1)
y = Asin2w - Asinw
y =2Acosw *sinw - Asinw
y = (2cosW -1) *x
cosw =(y/x+1)/2 = (x+y)/2x
so sinw = (1-cos2w)1/2 = ( 1 -(x+y/2x)2)1/2 = (3x2-y2-2xy)1/2 / 2x
putting in eqn 1
A = x/sinw = 2x2/(3x2-y2-2xy)1/2
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