what is the angle between the vectors A=2i^+2j^ with x axis
jugal deori
9 Years agoGrade 11
1 Answer
Allu Sidhu
9 Years ago
We know that dot product is A.B =(modA)(modB)cos(angle)(2i+2j).(I)=√8cos(angle)Therefore solving we get 45degreesHere another vector used is I because it x axis ..So we did dot product with I ..