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what is the angle between the vectors A=2i^+2j^ with x axis

jugal deori , 8 Years ago
Grade 11
anser 1 Answers
Allu Sidhu
We know that dot product is A.B =(modA)(modB)cos(angle)(2i+2j).(I)=√8cos(angle)Therefore solving we get 45degreesHere another vector used is I because it x axis ..So we did dot product with I ..
Last Activity: 8 Years ago
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