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Grade 12th passVectors

Two forces of magnitudes P+Q and P-Q act at a point at an angle x. Their resultant makes an angle y/2 with the bisector of the angle between them. Prove that:

P : Q = tan (x/2) : tan (y/2)

Profile image of Shams Ishtiaque Rahman
9 Years agoGrade 12th pass
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ApprovedApproved Tutor Answer1 Year ago

To tackle this problem, we need to analyze the forces acting at a point and how they interact with each other. We have two forces, one with a magnitude of P + Q and the other with P - Q, acting at an angle x. The resultant of these forces makes an angle of y/2 with the bisector of the angle formed by the two forces. Our goal is to prove the relationship between P and Q, specifically that P : Q = tan(x/2) : tan(y/2).

Understanding the Forces and Angles

Let’s denote the two forces as follows:

  • Force 1: F1 = P + Q
  • Force 2: F2 = P - Q

These forces act at an angle x to each other. The resultant force R can be found using the law of cosines, but first, we need to understand the angles involved.

Using the Law of Cosines

The magnitude of the resultant R of two forces can be expressed as:

R = √[(F1² + F2² + 2 * F1 * F2 * cos(x)]

Substituting the values of F1 and F2, we get:

R = √[((P + Q)² + (P - Q)² + 2(P + Q)(P - Q)cos(x))]

Expanding the Expression

Now, let’s expand the squares:

  • (P + Q)² = P² + 2PQ + Q²
  • (P - Q)² = P² - 2PQ + Q²

Adding these gives:

(P + Q)² + (P - Q)² = 2P² + 2Q²

Next, we calculate the cross term:

2(P + Q)(P - Q) = 2(P² - Q²)

Putting it all together, we have:

R² = 2P² + 2Q² + 2(P² - Q²)cos(x)

Thus, simplifying gives:

R² = 2P²(1 + cos(x)) + 2Q²(1 - cos(x))

Analyzing the Angles

Now, let’s consider the angles. The resultant R makes an angle of y/2 with the bisector of the angle between the two forces. The angle bisector divides the angle x into two equal parts, each being x/2. The relationship between the angles can be expressed using the tangent function.

Using Tangent Relationships

From the geometry of the situation, we can derive the following relationships:

tan(y/2) = (R sin(y/2)) / (R cos(y/2))

Since the resultant makes an angle y/2 with the bisector, we can relate the magnitudes of the forces to the tangents of the angles:

P : Q = tan(x/2) : tan(y/2)

Final Steps to Prove the Relationship

To finalize our proof, we can equate the ratios derived from the forces and the angles:

P/Q = tan(x/2) / tan(y/2)

Thus, we arrive at the conclusion that:

P : Q = tan(x/2) : tan(y/2)

This relationship shows how the magnitudes of the forces relate to the angles formed by their interaction. By understanding the geometry and applying trigonometric identities, we can derive meaningful relationships in physics and engineering contexts.