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Two forces act at an angle of 120°. The greater is represented by 80 kg weight and the resultant is at right angle to lesser. Find the latter
given greater force is 80kgAnd resultant makes 90degree with smaller one So assume smaller along X direction So the greater one will make 120 degree from X (or 30degree from Y) now net component along X should be zero.So 80kg(sin (30)) = smaller Forceso smaller force be 40kg weight
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