three forces of 30N, 20N, 10N … are acting alond three sides of equilateral triangle in cyclic order. find the magnitude, direction and position of the resultant.

please solve this question complete.

Forces A,B,C are 30N,20N,10N respectively. Let force A act along+ve x-axis thenForce A = 30iForce B = (20cos120°)i + (20sin120°)jForce C= (10cos240°)i +(10sin240°)jSo,Force A = 30iForce B= -10i +10√3jForce C= -5i -5√3jResultant force(Position)=15i +5√3jMagnitude of resultant = 10√3Direction of resultant = Resultant force vector/magnitude= (√3/2)i + (1/2)jI`ve answered all the questions.Hope you`ve understoodRegardsShubham Maurya,Student of Don Bosco AcademyPatna