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the x and y components of vector a are 4m and 6m respectively .the x and y cmponents of vector A+B are 10m and 9m respectively .find the length of B and angle that B makes with the axis.

the x and y components of vector a are 4m and 6m respectively .the x and y cmponents of vector A+B are 10m and 9m respectively .find the length of B and angle that B makes with the axis.

Grade:11

6 Answers

noogler
489 Points
8 years ago
A=4i+6j
A+B=10i+9j
B=(A+B)-A=6i+3j
length of B=(36+9)1/2=3(5)1/2
let o be angle made by B with X-axis..........Tano= -2     [Tano=-y/x]
 
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SuDheer Kumar Naidu Vundi
24 Points
8 years ago
how is it possible.....
here angle makes with x axis but not both x and y axis.... how we use tan(theta) here....
i think formula is given cos(theta) or sin(theta)
depends on coordinate system
Pankaj Raajpøøt Thakur
34 Points
6 years ago
A=4i+6jA+B=10i+9jB=(A+B)-A=6i+3jlength of B=(36+9)1/2=3(5)1/2let o be angle made by B with X-axisthus O=tan^-1(-1/2) [Tano=-y/x]
shinee
11 Points
6 years ago
but, how can it be negative ...i mean tan^-1(-1/2) , also in my book ans is tan^-1(1/2)  can u explain?
 
Yash k
11 Points
6 years ago
The above ans for the length of B is correct (45^1/2 or 3(5)^1/2)... But for tan(theta) it would be.. Tan(theta) = By/Bx = 3/6 = 1/2... Therefore, theta = tan^-1(1/2)
Yash Chourasiya
askIITians Faculty 256 Points
3 years ago
Hello Student

Please see the solution in the attachment.
643-1001_Untitled.png

I hope this answer will help you.

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