The unit vector perpendicular to the plane containing the vectors i-j+k and -i+j+k is?

Question

vishal kumar · Answer

the vector perpendicular to both vectors is obtained by doing the cross product of the two vectorsi.e (i-j+k)×(-i+j+k)=(−2i−2j) and the unit vector is =(1/8) 1/2 (-2i-2j)

beena chandran · Answer

to find the perpendicular vector .first take the cross product of the given 2 vectors. ie;(i-j+k)x(-i+j+k)= -2i-2j unit vector is=vector/magnitude of vector =(-2i-2j)/8^1/2

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The unit vector perpendicular to the plane containing the vectors i-j+k and -i+j+k is?

The unit vector perpendicular to the plane containing the vectors i-j+k and -i+j+k is?

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