The sum of the three vectors determined by the medians of a triangle directed from the vertices is
Bita Antil , 6 Years ago
Grade 12
1 Answers
Arun
Last Activity: 6 Years ago
Say that the triangle is ABC. The vector given the median from A to BC is (AC+AB)/2. Similarly, the one from B to AC is (BA+BC)/2, and the one from C to BA is (CB+CA)/2. Adding these, we get zero since CB=−BC, etc.
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