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Grade 11Vectors

the resultant of two vectors P and Q is R. if Q is doubled, the new resultant is perpendicular to P. Then R equals
(a) P
(b) (P+Q)
( c) Q
(d) (P-Q)
please explain how to solve

Profile image of Pushkar soni
11 Years agoGrade 11
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4 Answers

Profile image of Saurabh Kumar
11 Years ago

To tackle the problem involving vectors P and Q, we first need to understand the relationships between these vectors and their resultant. We know that the resultant of vectors P and Q is R, so we can express this mathematically as:

R = P + Q

Now, the problem states that if vector Q is doubled, the new resultant becomes perpendicular to vector P. Let's denote the new vector as Q' where:

Q' = 2Q

With this change, the new resultant R' can be expressed as:

R' = P + Q' = P + 2Q

For R' to be perpendicular to P, the dot product of R' and P must equal zero:

R' • P = 0

Substituting R' into the dot product condition gives us:

(P + 2Q) • P = 0

Expanding the dot product results in:

P • P + 2Q • P = 0

Here, P • P is simply the magnitude of vector P squared (let's denote it as |P|²), and Q • P is the dot product of vectors Q and P. This leads us to:

|P|² + 2(Q • P) = 0

From this equation, we can isolate Q • P:

2(Q • P) = -|P|²

Thus, we find:

Q • P = -\frac{|P|²}{2}

Next, we need to evaluate what R equals based on our original options. Initially, we expressed R as:

R = P + Q

Now, we can analyze the four options provided:

  • (a) R = P
  • (b) R = P + Q
  • (c) R = Q
  • (d) R = P - Q

Given that R = P + Q, we see that option (b) matches our expression for the resultant vector R. Since the problem states that the new resultant R' is perpendicular to P when Q is doubled, this condition does not alter the original relationship of R being P + Q.

Therefore, the correct answer is:

(b) R = P + Q

In summary, by establishing the relationship between the vectors, applying the condition for perpendicularity, and checking the options, we determined that the resultant vector R retains its original form as P + Q.

Profile image of Surya singh
8 Years ago
For first scene when resultant of P and Q is R
Vector R=Vector P +Vector Q
R=P2 +Q2+2PQCos\Theta….................equation 1
Then after doubling the magnitude of Q the new resultant is perpendicular to P..That means dot product of P and new resultant(R’) will be zero.
R’ * P=0...................equation 2
(where R’=P+2Q)
by putting value to equation 2
we get Cos\Theta = -P/2Q............equation 3
So from equation 1 and 3,we get 
R=Q
 
Profile image of Kushagra Madhukar
6 Years ago
Hello student
 
By law of vector addition, the resultant vector can be given as
R = P + Q
 
Now when Q is doubled the new resultant vector can be given as
R’ = P + 2Q
since, R’ is perpendicular to P
hence there dot product should be zero
or, R’ . P = 0
or, ( P + 2Q ).P = |P|2 + 2Q.P = 0
or, 2P.Q = -|P|2
 
Now,  |R|2 = |P|2 + |Q|2 + 2P.Q
                 =  |P|2 + |Q|2 – |P|2
                 =  |Q|2
or, R = Q
 
Hope it helps
Regards
Kushagra
Profile image of Yash Chourasiya
6 Years ago
Dear Student

643-1699_Untitled.png
Let the angle between two vectorsP and Qbeαand their resultant isR

So we can write

R2 = P2 + Q2 + 2PQcosα......[1]

When Q is doubled then let the resultant vector beR1, So we can write

R12= P2 + 4Q2 + 4PQcosα......[2]

Again by the given conditionR1is perpendicular toP

So4Q2 = P2 + R12......[3]

Combining [2] and [3] we get

R12 = P2 + P2 + R12 + 4PQcosα

⇒ 2PQcosα = −P2......[4]

combining [1] and [4] we get

R2 = P2 + Q2 − P2

⇒ R = Q

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya