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the resultant of two force f and 60n is 80n inclined at 60° to 60n determine magnitude and direction of F

the resultant of two force f and 60n is 80n inclined at 60° to 60n determine magnitude and direction of F

Grade:12th pass

1 Answers

Arun
25750 Points
5 years ago
 
Dear student,
The resultant force would be given by:
R=\sqrt{80^{2}+60^{2}+2\left ( 80 \right )\left ( 60 \right )cos\left ( 60^{0} \right )}=\sqrt{6400+3600+2\times 80\times 60\times \frac{1}{2}}=\sqrt{14800}=121.655 N
The direction would be given by:
Now, lets place the 60 N force along the horizontal direction so the 80 N force would be making an angle of 60 degree.
Hence if we say that the resultant force is making an angle \alpha with the horizontal, we would get:
Fcos\alpha =60+80cos60; Fsin\alpha=80 sin60Taking a ratio, would give the required result.
 
Regards
Arun

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