the position vector of a point lying on the line joining the points whose position vectors are i+j-k and i-j+k

Question

Sarfaraz Ahamed · Answer

The postion vector of any point lying on the line can be given by a+cb where ‘a’ is the postion vector of any point on the line required ‘b’ is the the direction vectore of the required line and ‘c’ is any constanst. therefore we can take ‘a’ to be either i+j-k or i-j+k, let us take i+j-k for this question and the direction vector ‘b’ can found by the direction vector of i+j-k to i-j+k by subtraction the latter one from the preceding one b= i-j+k – ( i+j-k) = -2j+2k hence the required vectore can be written as ( i+j-k)+c(-2j+2k)

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the position vector of a point lying on the line joining the points whose position vectors are i+j-k and i-j+k

the position vector of a point lying on the line joining the points whose position vectors are i+j-k and i-j+k

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