The line (x+6)/5=(y+10)/3=(z+14)/8 is the hypotenuse of a isosceles right angled triangle whose opposite vertex is (7,2,4). Find the equation of the remaining sides

Question

Arun · Answer

Dear student I am giving you a hint. The required lines are the lines passing through (7,2,4) which intersect the given line at an angle of 45&deg;. Lines will be x-7/3 = y-2/6 = z-2/4 And x-7/2 = y -2/-3 = z-4/6 Regards Arun (askIITians forum expert)

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The line (x+6)/5=(y+10)/3=(z+14)/8 is the hypotenuse of a isosceles right angled triangle whose opposite vertex is (7,2,4). Find the equation of the remaining sides

The line (x+6)/5=(y+10)/3=(z+14)/8 is the hypotenuse of a isosceles right angled triangle whose opposite vertex is (7,2,4). Find the equation of the remaining sides

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The line (x+6)/5=(y+10)/3=(z+14)/8 is the hypotenuse of a isosceles right angled triangle whose opposite vertex is (7,2,4). Find the equation of the remaining sides

The line (x+6)/5=(y+10)/3=(z+14)/8 is the hypotenuse of a isosceles right angled triangle whose opposite vertex is (7,2,4). Find the equation of the remaining sides

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