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```
Please tell me how [a b r]c+[b c r]a+[c a r]b=[a b c]r

```
2 years ago

```							Dear Akshat (a x b) x (r x c) = [a b c]r – [a b r]c                  …....(1) (a x b) x (r x c) = [b c a]r – [b c r]a                 ….......(2) (a x b) x (r x c) = [a b c]r – [a b r]c                ….......(3) Adding above 3 equations we get RHS as = 3 [a b c]r – {[a b r]c + [b c r]a – [c a r]b}              …........(4) again(a x b) x (r x c) = [a b c]r – [a b r]c                ….........(5) from (1) & (5)-[a b c]r – [a b r]c = [a r c]b – [b r c]aso[a b c]r = [a b r]c + [c a r]b + [b c r]a from (4)  [a b r]c+[b c r]a+[c a r]b=[a b c]r RegardsArun ()askIITians forum expert)
```
2 years ago
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