Please help me solve this asap.... the correct answer is (x+y-5) Question is attatched

Question

Samyak Jain · Answer

Given : a + x b + y c = 0 ...(1) and a x b + b x c + c x a = 6( b x c ) ...(2) To solve this question, we’ll represent a in terms of b and c since RHS in second equation is in terms of ( b x c ). We will use the facts that cross product of a vector with itself is a zero vector and negative of cross product of a vector with another vector is same as cross product of second vector with the first i.e. a x a = 0 and – ( a x b ) = ( b x a ) a + x b + y c = 0 , a = – (x b + y c ) Now, a x b = – (x b + y c ) x b = – (x( b x b) + y( c x b )) = – y( c x b ) = y( b x c ) [ b x b = 0 ] & c x a = c x {– (x b + y c )} = – c x (x b + y c ) = – (x ( c x b ) + y( c x c )) = – x( c x b ) = x( c x b ) [ c x c = 0 ] (2) becomes y( b x c ) + b x c + x( c x b ) = 6( b x c ) i.e. (x + y +1)( b x c ) = 6( b x c ) Comparing coefficients of b x c on both sides, we get (x + y +1) = 6 x + y – 5 = 0 .

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Please help me solve this asap.... the correct answer is (x+y-5) Question is attatched

Please help me solve this asap.... the correct answer is (x+y-5)

Question is attatched

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