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limx→a log(x-a)/log(ex-aa)

chaman , 11 Years ago
Grade 12
anser 1 Answers
Ajay Verma

Last Activity: 11 Years ago

ans:


use D.L. Hospital low :

limx--> a = log(x-a)/ log (ex-ea) undetermined form (- infinite/ - infinite)

D.L. Hospital low ( differentiate Nrand Dr)
limx--> a = (ex-ea)/( x-a) ex again at x=a 0/0 form

again D.L. Hospital low ( differentiate Nrand Dr)
limx--> a = ex/ {xex + ex- aex}
now put the limit x--> a
= 1



Thanks and Regards,
Ajay verma,
askIITians faculty,
IIT HYDERABAD

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