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lim x → a log(x-a)/log(e x -a a )

limx→a       log(x-a)/log(ex-aa)

Grade:12

1 Answers

Ajay Verma
askIITians Faculty 33 Points
7 years ago
ans:

use D.L. Hospital low :

limx--> a = log(x-a)/ log (ex-ea) undetermined form (- infinite/ - infinite)

D.L. Hospital low ( differentiate Nrand Dr)
limx--> a = (ex-ea)/( x-a) ex again at x=a 0/0 form

again D.L. Hospital low ( differentiate Nrand Dr)
limx--> a = ex/ {xex + ex- aex}
now put the limit x--> a
= 1



Thanks and Regards,
Ajay verma,
askIITians faculty,
IIT HYDERABAD

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