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let the unit vectors a and b be perpendicular to each other and unit vector c be inclined at an angle theta to both a and b if c=xa+yb+z(a×b) then (1)x=costheta,y=sintheta,z=cos2theta (2)x=sintheta,y=costheta,z=-cos2theta (3)x=y= costheta,z^2=cos2theta (4)x=y=costheta,z^2=-cos2theta
let the unit vectors a and b be perpendicular to each other and unit vector c be inclined at an angle theta to both a and b if c=xa+yb+z(a×b) then (1)x=costheta,y=sintheta,z=cos2theta (2)x=sintheta,y=costheta,z=-cos2theta (3)x=y= costheta,z^2=cos2theta (4)x=y=costheta,z^2=-cos2theta


3 years ago

Arun
25768 Points
							Dear Akshat we have c =xa + yb +z (a x b)c.a = xand c.b = yhence x = y = cos theta now c.c = c^2(xa + yb +z (a x b)).(xa + yb +z (a x b)) =  |c|^2 2 x^2 +z^2 |a|^2 |b|^2 – (a.b)^2 = 12 x^2 + z^2 – 0 = 1since a and b are perpendicular to each other hence z^2  = 1 – 2x^2 = 1- 2 cos^2theta = – cos 2$\theta$ hence option 4 is correct regardsArun (askIITians forum expert)

3 years ago
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