Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
let the unit vectors a and b be perpendicular to each other and unit vector c be inclined at an angle theta to both a and b if c=xa+yb+z(a×b) then (1)x=costheta,y=sintheta,z=cos2theta (2)x=sintheta,y=costheta,z=-cos2theta (3)x=y= costheta,z^2=cos2theta (4)x=y=costheta,z^2=-cos2theta
Dear Akshat we have c =xa + yb +z (a x b)c.a = xand c.b = yhence x = y = cos theta now c.c = c^2(xa + yb +z (a x b)).(xa + yb +z (a x b)) = |c|^2 2 x^2 +z^2 |a|^2 |b|^2 – (a.b)^2 = 12 x^2 + z^2 – 0 = 1since a and b are perpendicular to each other hence z^2 = 1 – 2x^2 = 1- 2 cos^2theta = – cos 2 hence option 4 is correct regardsArun (askIITians forum expert)
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -