let the unit vectors a and b be perpendicular to each other and unit vector c be inclined at an angle theta to both a and b if c=xa+yb+z(a×b) then (1)x=costheta,y=sintheta,z=cos2theta (2)x=sintheta,y=costheta,z=-cos2theta (3)x=y= costheta,z^2=cos2theta (4)x=y=costheta,z^2=-cos2theta

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Arun · Answer

Dear Akshat we have c =xa + yb +z (a x b) c.a = x and c.b = y hence x = y = cos theta now c.c = c^2 (xa + yb +z (a x b)).(xa + yb +z (a x b)) = |c|^2 2 x^2 +z^2 |a|^2 |b|^2 – (a.b)^2 = 1 2 x^2 + z^2 – 0 = 1 since a and b are perpendicular to each other hence z^2 = 1 – 2x^2 = 1- 2 cos^2theta = – cos 2 hence option 4 is correct regards Arun (askIITians forum expert)

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let the unit vectors a and b be perpendicular to each other and unit vector c be inclined at an angle theta to both a and b if c=xa+yb+z(a×b) then (1)x=costheta,y=sintheta,z=cos2theta (2)x=sintheta,y=costheta,z=-cos2theta (3)x=y= costheta,z^2=cos2theta (4)x=y=costheta,z^2=-cos2theta

let the unit vectors a and b be perpendicular to each other and unit vector c be inclined at an angle theta to both a and b if c=xa+yb+z(a×b) then (1)x=costheta,y=sintheta,z=cos2theta (2)x=sintheta,y=costheta,z=-cos2theta (3)x=y= costheta,z^2=cos2theta (4)x=y=costheta,z^2=-cos2theta

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