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`        Let ABCD be a parallelogram such that AB= q and AD = p and angle BAD be an acute angle. If r is teh vector that coincides with the altitude directed from vertex B to side AD then r is given by? (1) r= -3q + ((3(p.q))/(p.p))p(2) r = 3q - ((3(p.q))/(p.p))p (3) r= -q + (((p.q))/(p.p))p(4) r= q - (((p.q))/(p.p))p`
2 years ago

```							Dear Student AE = vector component of q on pAE = (p.q) p/(p.p) From triangle ABEAB + BE = AEq + r = (p.q)p/(p.p)q = -r + (p.q)p/(p.p)Hence option 3 is correct. RegardsArun (askIITians forum expert)
```
2 years ago
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### Course Features

• 19 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions