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Let ABCD be a parallelogram such that AB= q and AD = p and angle BAD be an acute angle. If r is teh vector that coincides with the altitude directed from vertex B to side AD then r is given by? (1) r= -3q + ((3(p.q))/(p.p))p (2) r = 3q - ((3(p.q))/(p.p))p (3) r= -q + (((p.q))/(p.p))p (4) r= q - (((p.q))/(p.p))p

Let ABCD be a parallelogram such that AB= q and AD = p and angle BAD be an acute angle. If r is teh vector that coincides with the altitude directed from vertex B to side AD then r is given by?
 
(1) r= -3q + ((3(p.q))/(p.p))p
(2) r = 3q - ((3(p.q))/(p.p))p
 
(3) r= -q + (((p.q))/(p.p))p
(4) r= q - (((p.q))/(p.p))p

Grade:12

1 Answers

Arun
25763 Points
3 years ago
Dear Student
 
AE = vector component of q on p
AE = (p.q) p/(p.p)
 
From triangle ABE
AB + BE = AE
q + r = (p.q)p/(p.p)
q = -r + (p.q)p/(p.p)
Hence option 3 is correct.
 
Regards
Arun (askIITians forum expert)

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