×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

let a=i+j and b=2i-k then point of intersection of the lines r×a=b×a and r×b=a×b is (1)-i+j+k (2)3i-j+k (3)3i+j-k (4)i-j-k


2 years ago

Arun
24742 Points
							Dear Akshat r x a = b x a(r – b) x a = 0r – b is parallel to ahence r – b = $\lambda$ ai.e.r = b + $\lambda$ asimilarly, r x b = a x b can be written asr = a + $\mu$ bfor point of intersection of these lineswe getb + $\lambda$ a = a + $\mu$ b$\lambda$ = $\mu$ = 1 hence the required point of intersection isr = a+ b = i +j + 2 i – k = 3 i +j – k hence option 3 is correct regardsArun (askIITians forum expert)

2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Vectors

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 19 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions