in the same above questionrectangular hexagon AB+AC+AD+AE+AF=6AO
MOHIT , 5 Years ago
Grade 12th pass
Vectors> in the same above question rectangular he...
1 Answers
Aditya Gupta
Last Activity: 5 Years ago
hello mohit you havent attached a pic, but i ll still ans the ques :)
AB+AC+AD+AE+AF=AB+(AC+AF)+AD+AE
=AB+(AC+CD)+AD+AE [since AF=CD]
=AB+AD+AD+AE
=2AD+(AB+AE)
=2AD+(ED+AE) [since AB=ED]
=2AD+AD
=3AD
=3*(2AO) [since O is the center and AO=OD]
=6AO
=AB+(AC+CD)+AD+AE [since AF=CD]
=AB+AD+AD+AE
=2AD+(AB+AE)
=2AD+(ED+AE) [since AB=ED]
=2AD+AD
=3AD
=3*(2AO) [since O is the center and AO=OD]
=6AO
kindly approve :)
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