In a triangle ABC , If 'O' is the circumcentre and 'H' is the orthocentre, then show that

1) OA + OB + OC = OH

& 2) HA+HB+HC =2HO.

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we know that O'G =2GO  where G is the centroid of trianglelet a point D between B and CSo, OD =(OB+OC )/2now OA + OB + OC = OA + 2ODwe know that G devide the point A and mib point of apposite side(D) in ratiio  2:1So, OG =(OA 2OD)/(2+1)So, OA + OB + OC =3OG=2OG + OG=GO'+OG =OO'