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if x+iy=3/2+cosa+isina, then find the value of x^2+y^2

if x+iy=3/2+cosa+isina, then find the value of x^2+y^2

Grade:12

2 Answers

Deepak Kumar Shringi
askIITians Faculty 4407 Points
4 years ago
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Khimraj
3007 Points
4 years ago
x+iy= (3/2 + cosa) + isina – (1)
So,
x-iy= (3/2 + cosa) - isina      -(2)
Then multiply equation (1) and (2)
x2 + y2 = (¼)*(13 +  12cosa).
Hope it clears.

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