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If vector a+ vector b=vector c & |vector a|=3|,vector b|=4 ,|vector c|=5.then find between vector a and vector b
Let the angle b/w them be Q.Using formula, |c|2 = |a|2 + |b|2 + 2|a||b|cosQwe get:- 52 = 32 + 42 + 2*4*3*cosQ0 = 24cosQtherefore, cosQ = 0 = cos90thus, Q = 90 degreesHope it helps
Let the angle b/w them be Q.
Using formula, |c|2 = |a|2 + |b|2 + 2|a||b|cosQ
we get:- 52 = 32 + 42 + 2*4*3*cosQ
0 = 24cosQ
therefore, cosQ = 0 = cos90
thus, Q = 90 degrees
Hope it helps
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