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IF ABCDEF is a regular hexagon.If G is the centre of the hexagon,then AB+AC+AD+AE+AF=A) 3AG B) 2AG C) 6AG D) 4AG
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AB+AC+AD+AE+AF=(AB+AE)+(AC+AF)+AD=AD+AD+AD+=3AD=3(2AG)=6AGtherefore,AB+AC+AD+AE+AF=3(2AD)=6AG RegardsArun (askIITians forum expert)
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