if a b c are three non zero vectors then prove that [a b c]^2 =a^2b^2c^2.

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Arun · Answer

[a b c] 2 = {a. (b X c)} 2 = a 2 (b X c) 2 cos theta = a 2 b 2 c 2 cos theta sin alpha = if we find mod then = a 2 b 2 c 2 Regards Arun (askIITians forum expert)

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if a b c are three non zero vectors then prove that [a b c]^2 =a^2b^2c^2.

if a b c are three non zero vectors then prove that [a b c]^2 =a^2b^2c^2.

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if a b c are three non zero vectors then prove that [a b c]^2 =a^2b^2c^2.

if a b c are three non zero vectors then prove that [a b c]^2 =a^2b^2c^2.

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