Grade 12Mechanics
If (a×b)²+(a dot b)²=144 and |a|=4 then find b vector
1 Answer
deepak
axb = |a||b|sin(x)
a.b= |a||b|cos(x)
(a×b)²+(a dot b)²= a2b2 =144
hence if a=4 then b=+3
hope this was usefull
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