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|A×B|/A.B=√3
=> ABsin x / ABcos x= √3 (Considering the angle between the two vectors as x)
=> tanx =√3
=> x= π/3
=> |A+B|=√(A^2 + B^2 +2AB cos x)
=> |A+B|=√(A^2 + B^2 +2AB* 1/2) [Since cos π÷3 = 1/2]
=> |A+B|=√(A^2 + B^2 + AB)
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Arun (askIITians forum expert)
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