I had exam day after tomorrow. Plz solve the whole exercise 2 for me . All the questions from 1 to 9 . Questions are in the attachment.

Question

sahil · Answer

Solving one by one first no 1.Sol:unit vector of vector 6i+2j+3k is 6i+2j+3k/7 and to 3i-2j is 3i-2j/(13)^/12

sahil · Answer

2:cos of angle between vector a and b is a.b/|a||b| here let a be 2i-2j+4k and b be 3i+j+2k .Solve to get a.b (6-2+8)=12 |a||b|=4(21)^1/2 now cos = (3/7)^1/2 now sin is (1-cos^2)^1/2 solve to get sin =(4/7)^1/2

sahil · Answer

3:a×(b×c)=(a.c)b-(a.b)c this is a simple formula and we have also express it as combination of a, b and c.

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

I had exam day after tomorrow. Plz solve the whole exercise 2 for me . All the questions from 1 to 9 . Questions are in the attachment.

I had exam day after tomorrow. Plz solve the whole exercise 2 for me . All the questions from 1 to 9 . Questions are in the attachment.

3 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Vectors

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship