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From the top of a tower two particles are dropped at an interval of 2second.find the relative velocity and relative acceleration of the particles during the fall.accleration due to gravity=g cm/s

Shinjani Biswas , 6 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 6 Years ago

Dear student
 
V1 = 0 + gt1
 
V2 = 0 + g (t1-2)
 
Now relative velocity = V1 - V2 = 2g cm/sec
 
Now
Since acceleration will be same for both the particles, hence 
Relative acceleration = g-g = 0

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