#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# FIND UNIT VECTORS PERPENDICULAR TO THE PLANE DETERMINED BY THE POINTS P(1,-1,2) , Q(2,0,-1) AND R(0,2,1).

Y RAJYALAKSHMI
45 Points
7 years ago
The two vectors in the given plane is PQ & PR
PQ = (2 – 1) i + (0 + 1) j + (-1 – 2)k = i + j – 3k
PR = (0 – 1)i + (2 + 1) j + (1 – 2k = –i + 3j – k

The vector perpendicular to PQ & PR is PQ x PR
= 8i + 4j + 4k

So, The unit vector perpendicular to the plane is (8i + 4j + 4k)/ sq. root ( 82 + 42+ 42)
= (2i + j + k )/sq. root (6)

Bharat Makkar
34 Points
7 years ago
THANKS!!!!

SHAIK HAFEEZUL KAREEM
109 Points
5 years ago

The two vectors in the given plane is PQ & PR
PQ = (2 – 1) i + (0 + 1) j + (-1 – 2)k = i + j – 3k
PR = (0 – 1)i + (2 + 1) j + (1 – 2k = –i + 3j – k

The vector perpendicular to PQ & PR is PQ x PR
= 8i + 4j + 4k

So, The unit vector perpendicular to the plane is (8i + 4j + 4k)/ sq. root ( 82 + 42+ 42)
= (2i + j + k )/sq. root (6)