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Grade: 12
        
Could you please help me by answering this question elaborately.....
2 months ago

Answers : (2)

Arun
23747 Points
							
Dear student
 
it is (a.b + a.c ) x (a + 2b + 3c)
 
 = (a.b) x a + (a.b) x 2b + (a.b) x 3c + (a.c) x a + (a.c) x 2b + (a.c) x 3c
 
 = 0 + 0 + 3 [ a b c] + 0  – 2 [ a b c] + 0
 
 = [ a b c]
 
Hope it helps
2 months ago
Vikas TU
10400 Points
							
Dear student 
a.{ b× a + 2 b×b + 3 b×c + c×a + 2c×b + 3 c×c)
a.{ b×a + 3 b×c + c× a - 2 b×c )
a. ( b× a + c× a + b× c)
a.( b×a) + a.( c×a) + a.( b×c)
As a.( b×a) and a.( c×a) =0
So a .( b×c) = [ a b c]
Good Luck 
2 months ago
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