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# Could you please help me by answering this question elaborately.....

Grade:12

## 2 Answers

Arun
25763 Points
2 years ago
Dear student

it is (a.b + a.c ) x (a + 2b + 3c)

= (a.b) x a + (a.b) x 2b + (a.b) x 3c + (a.c) x a + (a.c) x 2b + (a.c) x 3c

= 0 + 0 + 3 [ a b c] + 0  – 2 [ a b c] + 0

= [ a b c]

Hope it helps
Vikas TU
14149 Points
2 years ago
Dear student
a.{ b× a + 2 b×b + 3 b×c + c×a + 2c×b + 3 c×c)
a.{ b×a + 3 b×c + c× a - 2 b×c )
a. ( b× a + c× a + b× c)
a.( b×a) + a.( c×a) + a.( b×c)
As a.( b×a) and a.( c×a) =0
So a .( b×c) = [ a b c]
Good Luck

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