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angle between diagonals of a parallelogram whose side represented by vector a =2i +j +k and vector b = i -j - k.Options areA) cos^-1 (1/3)B) cos^-1 (1/2)C) cos^-1 (4/9)D) cos^-1 (5/9)

ayush Sharma , 7 Years ago
Grade 11
anser 2 Answers
Shailendra Kumar Sharma

Last Activity: 7 Years ago

Cos(Theta) =A.B./ABSo the angle will be Cos (Theta) = (​2i +j +k). (i -j - k) /( \sqrt{4+1+1})*\sqrt{(1+1+1))}\Theta =(2-1-1)/\sqrt{6} X\sqrt{3}) =0So the angle is 90 Degree as cos 90 is zero

Subham

Last Activity: 4 Years ago

We can find digonal vector a+b and a-b by this we can use formula cos theta equals to (a-b)(a+b)/|a+b||a-b| we got cos theta equals to 1/3

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