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A VECTOR OF MAGNITUDE ‘a’ IS ROTATED THROUGH ANGLE THETA.WHAT IS THE MAGNITUDE OF THE CHANGE IN THE VECTOR?

Bharat Makkar , 10 Years ago
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anser 3 Answers
shashi K Sharma

Last Activity: 10 Years ago

Dear Bharat
As the vector has been rotated by angle theta,
Let the final vector be called as vf , while the initial being vi 
The magnitude of change in vector is | vf  – vi | = ( vi2 + vf2 - 2vivfCos(theta))^0.5
as the magnitude is same say ‘v’
thus the expression reduces to 2vSin(theta/2)
 
Kindly note that change in magniyude is zero while magnitude of change in vector is 2vSin(theta/2)
Hope this rustic expression is not that pesky.

Bharat Makkar

Last Activity: 10 Years ago

THANKS FOR ALL THE ANSWERED PROBLEMS.

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,
Please find the solution to your problem.
 
As the vector has been rotated by angle θ,
Let the final vector be called as vf , while the initial being vi 
The magnitude of change in vector is | vf  – vi | = ( vi2 + vf2 - 2vivfCosθ)1/2
as the magnitude is same say , |vi| = |vf| = v
thus the expression reduces to 2vSin(θ/2)
Kindly note that change in magnitude is zero while magnitude of change in vector is 2vSin(θ/2)
 
Thanks and regards,
Kushagra

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