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A VECTOR OF MAGNITUDE ‘a’ IS ROTATED THROUGH ANGLE THETA.WHAT IS THE MAGNITUDE OF THE CHANGE IN THE VECTOR?

A VECTOR OF MAGNITUDE ‘a’ IS ROTATED THROUGH ANGLE THETA.WHAT IS THE MAGNITUDE OF THE CHANGE IN THE VECTOR?

Grade:Select Grade

3 Answers

shashi K Sharma
46 Points
6 years ago
Dear Bharat
As the vector has been rotated by angle theta,
Let the final vector be called as vf , while the initial being vi 
The magnitude of change in vector is | v – vi | = ( vi2 + vf2 - 2vivfCos(theta))^0.5
as the magnitude is same say ‘v’
thus the expression reduces to 2vSin(theta/2)
 
Kindly note that change in magniyude is zero while magnitude of change in vector is 2vSin(theta/2)
Hope this rustic expression is not that pesky.
Bharat Makkar
34 Points
6 years ago
THANKS FOR ALL THE ANSWERED PROBLEMS.
Kushagra Madhukar
askIITians Faculty 629 Points
one year ago
Dear student,
Please find the solution to your problem.
 
As the vector has been rotated by angle θ,
Let the final vector be called as vf , while the initial being vi 
The magnitude of change in vector is | v – vi | = ( vi2 + vf2 - 2vivfCosθ)1/2
as the magnitude is same say , |vi| = |vf| = v
thus the expression reduces to 2vSin(θ/2)
Kindly note that change in magnitude is zero while magnitude of change in vector is 2vSin(θ/2)
 
Thanks and regards,
Kushagra

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