A force of magnitude 5unit in the direction of vector i^+j^+k^ is displaindi the particle from point (1,1,1) to (2,1,3). Find work done by force.

Question

Arun · Answer

Dear student as work done = F . S F = 5 (i + j+ k) / sqrt(3) Also displacement vector = i + 2k hence work done = F. S = 5/ sqrt(3) + 10 / sqrt(3) = 15 / sqrt(3) = 5* sqrt(3)

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A force of magnitude 5unit in the direction of vector i^+j^+k^ is displaindi the particle from point (1,1,1) to (2,1,3). Find work done by force.

A force of magnitude 5unit in the direction of vector i^+j^+k^ is displaindi the particle from point (1,1,1) to (2,1,3). Find work done by force.

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A force of magnitude 5unit in the direction of vector i^+j^+k^ is displaindi the particle from point (1,1,1) to (2,1,3). Find work done by force.

A force of magnitude 5unit in the direction of vector i^+j^+k^ is displaindi the particle from point (1,1,1) to (2,1,3). Find work done by force.

1 Answers

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