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A car with a speed of 10 m/s is in the direction of r vector =-4 i cap +3j cap . The velocity of the car is
V = | V | v^V = 10 r^V = 10 ( r / | r | )V= 10 (-4i^+3j^/✓(((-4)^(2))+((3)^(2))) )V= 10 (-4i^+3j^/ 5)V= 2(-4i^+3j^)V= -8i^ + 6j^ RegardsArun (askIITians forum expert)
V = | V | v^
V = 10 r^
V = 10 ( r / | r | )
V= 10 (-4i^+3j^/✓(((-4)^(2))+((3)^(2))) )
V= 10 (-4i^+3j^/ 5)
V= 2(-4i^+3j^)
V= -8i^ + 6j^
Regards
Arun (askIITians forum expert)
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