0

Guest

Courses New

A block of mass M is moving on a smooth horizontal surface with constant speed u. Bullets arefired horizontally against the block to reduce the velocity of the block to half its initial value.Bullets get embedded in the block. Mass of each bullet is ‘m’ and speed ‘u’. Then the number ofbullets required is–

A block of mass M is moving on a smooth horizontal surface with constant speed u. Bullets arefired horizontally against the block to reduce the velocity of the block to half its initial value.Bullets get embedded in the block. Mass of each bullet is ‘m’ and speed ‘u’. Then the number ofbullets required is–

Grade:11

1 Answers

Eshan
askIITians Faculty 2095 Points
5 years ago
Since there is no external force acting on the system during collision, the linear moment of bullet+block system will be conserved.

Initial momentum of block=Mu
Final momemntum of block after its speed gets reduced to half=\dfrac{1}{2} Mu

The reduction of momentum will be imparted by the incoming bullets in the direction opposite to that of the block. Let the number of bullets ben.

HenceMu-(n)mu=\dfrac{1}{2}Mu
\implies n=\dfrac{M}{2m}

Think You Can Provide A Better Answer ?

Other Related Questions on Vectors

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More