MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
A ball rolls off the edge of a horizontal plane 4.9 m high. It strikes the floor at a point 10 m horizontally away from the edge of the plane, then the speed of the ball at the instant it left the plane is?
B)5 m/s
C)20 m/s
D)10 m/s
E)40 m/s
one year ago

Answers : (2)

Tanuja
33 Points
							Time taken =√2h/g  =  √2*4.9/9.8= 1Given range = 10U*t= 10U*1 = 10U = 10It leaves plane with velocity 10 m/s
						
one year ago
Rahul Raman
12 Points
							It should be 10m/s because x=4.9t² gives t= 1s. Hence the ball would require 1s to fall  if it were to fall freely under gravity. The same would be the time required to move horizontally. Thus the equation v=s/t gives v= 10m/s.
						
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 3,180 off

COUPON CODE: SELF20


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 19 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 127 off

COUPON CODE: SELF20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details