3. Let the angle between two nonzero vectors A and B be 120° and its resultant be C. (a) C must be equal to |A-B| (b) C must be less than |A-B| (c) C must be greater than |A-B| (d) C may be equal to |A-B|

3. Let the angle between two nonzero vectors A and B be 120° and its

Arun

you can try formula, which is-

R^2= P^2 +Q^2 +2PQ cos $\theta$ where R is Resultant

You will surely get answer.

But if we see that |A−B| will happen if both the vectors are in opposite direction that means angle is 180 degree.

but here in question is 120 degree hence it will surely be greater than |A-B|.

Last Activity: 8 Years ago

vishal tarte

if c is thehave resultant of A and B,then . C sqrt=A^2+B^2-AB. [cos120=-1\2] similarly, -C=|A-B|=sqrt,A^2+B^2-2ABcos120 =sqrt A^2+B^2+AB so,|A-B|>c

Last Activity: 8 Years ago

Muneeb

They ar

Last Activity: 6 Years ago

Krish Gupta

Just go with this formula :

R^2= P^2 +Q^2 +2PQ cos $\theta$ where R is Resultant

But if we see that |A−B| will happen if both the vectors are in the opposite direction that means angle is 180 degree.

but here in question is 120 degree hence it will surely be greater than |A-B|.

Last Activity: 5 Years ago

Kushagra Madhukar

Dear Student,

Please find the attached answer to your question.

as we know, R² = A² + B² + 2ABcosθ

ascosθ decreases as we go from θ = 0 to θ = 180, so does the magnitude of the vector R,

The minimum magnitude for vector R can be |A – B| at θ = 180.

Hence, the resultant vector at θ = 120 is greater than |A – B|.

Hope it helps.

Thanks and regards,

Kushagra

Last Activity: 5 Years ago

Vectors> 3. Let the angle between two nonzero vect...

3. Let the angle between two nonzero vectors A and B be 120° and its resultant be C.
(a) C must be equal to |A-B|
(b) C must be less than |A-B|
(c) C must be greater than |A-B|
(d) C may be equal to |A-B|

Carlyn medona , 8 Years ago

Arun

vishal tarte

Muneeb

Krish Gupta

Kushagra Madhukar

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Vectors> 3. Let the angle between two nonzero vect...

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Carlyn medona , 8 Years ago

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