what is thesquare root of -iargument of -i
Samarth Khandelwal , 11 Years ago
Grade 11
Vectors> complex-numbers...
4 Answers
Chetan Mandayam Nayakar
Last Activity: 11 Years ago
sqrt(-i)=e-i((pi/2)+(2N(pi)))
where N is ANY integer
Akash Kumar Dutta
Last Activity: 11 Years ago
find sq root by the simple step... root (-i)=a+ib...............
and arg of -i= -pi/2 or 5pi/2
sandy sandy
Last Activity: 11 Years ago
arg is 270 ad 1is the root
Harsh Gupta
Last Activity: 11 Years ago
Argument if -i is -π/2.
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