badge image

Enroll For Free Now & Improve Your Performance.

User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.

Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Grade: 11


Four forces of magnitude P,2P,3P and 4P act aling the four sides of square ABCD in cyclic order. Use the vector method to find the resultant force?

11 years ago

Answers : (2)

Rahul Parkar
8 Points

side 1 parallel side 3

considering this as X-axis,

P-3P=-2P i          (→ +ive)

for Y-axis

2P-4P=-2P j        (↑ +ive)





11 years ago
Kushagra Madhukar
askIITians Faculty
605 Points
Dear student,
Please find the solution to your problem.
We have,
FAB = P i
FBC = 2P j
FCD = 3P ( – i)
FDA = 4P ( – j)
Hence, resultant vector,
Fr = FAB + FBC + FCD + FDA
    = (P i – 3P i) + (2P j – 4P j)
    = – 2P i – 2P j
Hence, |Fr| = [(-2P)2 + (-2P)2]1/2
Hence, |Fr| = 2√2 P
Thanks and regards,
4 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution

Course Features

  • 19 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details