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for obtice angle , direction cosine should be -ve ...
X = i + j + k
Y = i + 3j - k
here we have two possible vectors which are perpendicular to X & Y ..
P(vector perpendicular to both X & Y) = XxY or YxX (x represents cross product)
P = -4i + 2j + 2k or 4i - 2j - 2k
I II
required solution is II coz it is making an obtuce angle with z axis coz direct cosine is -ve ..
P = 4i - 2j - 2k
P(unit vector) = (4i - 2j -2k)/modP = (4i - 2j - 2k)/root24 ans
modP = root(16+4+4) = root24
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