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a certain force has magnitude of 200N, its x component is -80N. what is its y component and its direction? two possible answers exist ... reply quickly..
F = 200
Fcos@ = Fx (x compponent )) ...............1
Fsin@ = Fy ( y component ) .............2
from 1
200cos@ = -80
cos@ = -2/5
here @ can be in 2nd or 3rd quadrant ,
if @ is in 2nd quadrant then cos@ is -ve, sin@ is +ve@
cos@ = -2/5 , sin@ = (1-cos2@)1/2 = (21)1/2/5
now , Fy = F sin@ = 200(21)1/2/5 = 184N
if @ is in 3rd quadrant then cos@ is -ve , sin@ is -ve
cos@ = -2/5 , sin@ = -(21)1/2/5
Fy = Fsin@ = -184N
therefore two possible answers are 184N & -184N
aprove if u like my ans
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