Fawz Naim
Last Activity: 14 Years ago
the resultant of the two vectors will lie along the bisctor
resultant R=sqr root(A^2+A^2+2.A.Acos?)
=sqr root(A^2+A^2+2A^2cos?)
=sqr root(2A^2+2A^2cos?)
=sqr root(2A^2[1+cos?])
=A*sqr root(2[2cos^?/2])
=A*2cos?/2
2Acos?/2. therefore option (a) is correct