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A regular hexagon has vertices ABCDEF and it is centered at the origin O. Express the following vectors in terms of a=OA and b=OB AB,BC,AD,CF,AC, and BC+DE+FA
A regular hexagon has vertices ABCDEF and it is centered at the origin O. Express the following vectors in terms of a=OA and b=OB
AB,BC,AD,CF,AC, and BC+DE+FA
Generally two laws of vectors are useed to solve the problem: 1.triangle law 2. parallogram law as shown if in fig1 and respectively. In last fig hexgon drawn follow as per rules and get solution like as............ from triangle OAB AB=b-a AD=OD-OA (OD=-OA=-a) AD=-2a From triangle OBC OB+BC=OC To find OC from triangle OAC...........OA+AC=OC............. ( To find AC ..from OABC parllogram AC=-OA+AB=b-2a) Now OC=a+b-2a=b-a BC=-2a remainig U can find similar procedure . IF u have any doubts feel free to ask. We are here to help your IIT preparation. All the best.
Generally two laws of vectors are useed to solve the problem: 1.triangle law
2. parallogram law as shown if in fig1 and respectively.
In last fig hexgon drawn follow as per rules and get solution like as............
from triangle OAB
AB=b-a
AD=OD-OA (OD=-OA=-a)
AD=-2a
From triangle OBC
OB+BC=OC
To find OC from triangle OAC...........OA+AC=OC............. ( To find AC ..from OABC parllogram AC=-OA+AB=b-2a)
Now OC=a+b-2a=b-a
BC=-2a
remainig U can find similar procedure .
IF u have any doubts feel free to ask. We are here to help your IIT preparation.
All the best.
Thanks a lot. but I don't see why BC would be -2a and not just -a
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