Join now for JEE/NEET and also prepare for Boards Learn Science & Maths Concepts for JEE, NEET, CBSE @ Rs. 99! Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
A regular hexagon has vertices ABCDEF and it is centered at the origin O. Express the following vectors in terms of a=OA and b=OB
AB,BC,AD,CF,AC, and BC+DE+FA
Generally two laws of vectors are useed to solve the problem: 1.triangle law
2. parallogram law as shown if in fig1 and respectively.
In last fig hexgon drawn follow as per rules and get solution like as............
from triangle OAB
AB=b-a
AD=OD-OA (OD=-OA=-a)
AD=-2a
From triangle OBC
OB+BC=OC
To find OC from triangle OAC...........OA+AC=OC............. ( To find AC ..from OABC parllogram AC=-OA+AB=b-2a)
Now OC=a+b-2a=b-a
BC=-2a
remainig U can find similar procedure .
IF u have any doubts feel free to ask. We are here to help your IIT preparation.
All the best.
Thanks a lot. but I don't see why BC would be -2a and not just -a
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !