Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A regular hexagon has vertices ABCDEF and it is centered at the origin O. Express the following vectors in terms of a=OA and b=OB AB,BC,AD,CF,AC, and BC+DE+FA

A  regular hexagon has vertices ABCDEF and it is centered at the origin O. Express the following vectors in terms of a=OA and b=OB


AB,BC,AD,CF,AC, and BC+DE+FA

Grade:

2 Answers

DilipReddy Ask IITians expert-IITB
36 Points
11 years ago

Generally two laws of vectors are useed to  solve the problem: 1.triangle law 

2. parallogram law as shown if in fig1 and respectively.

1079_22425_2.jpg

In last fig hexgon drawn follow as per rules and  get solution like as............

from triangle OAB

AB=b-a

AD=OD-OA     (OD=-OA=-a)

AD=-2a

From triangle OBC

OB+BC=OC

To find OC   from triangle OAC...........OA+AC=OC.............          ( To find AC ..from OABC parllogram AC=-OA+AB=b-2a)

Now OC=a+b-2a=b-a

BC=-2a

remainig U can find similar procedure .

IF u have any doubts feel free to ask. We are here to help your IIT preparation.

All the best.

 

Aarin Covyeau
4 Points
11 years ago

Thanks a lot. but I don't see why BC would be -2a and not just -a

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free