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Grade: 12th pass
`        what is the minimum value of (9sec^2x+4cosec^2x+7)?`
one year ago

## Answers : (1)

Arun
24739 Points
```							The given function can be written as9 (1 + tan2ɸ) + 5(1 + cot2ɸ) + 7= 9 + 4 + 9 tan2ɸ + 4 cot2ɸ + 7= (13) + (9 tan2ɸ + 4 cot2ɸ) + 7Now observe that we have the formula for finding min value of 9 tan2ɸ + 4 cot2ɸSo here minimum value is(13+ 2√(9*4) + 7 = 25 + 7 = 32
```
one year ago
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