what is proof of 1) sin (A + B +C) = sinAcosBcosC + cosAsinBcosC + cosAcosBsinC - sinAsinBsinC

Question

Himanshu · Answer

L.H.S. : sin(A+B+C) = sin((A+B)+C) =sin(A+B)cosC + cos(A+B)sinC =[sinAcosB + cosAsinB]cosC + [cosAcosB – sinAsinB)sinC =sinAcosBcosC + cosAsinBcosC + cosAcosBsinC - sinAsinBsinC =R.H.S. Hence. proved .

Sourabh Singh · Answer

Open up for sum of angles Sin(A+B+C) sin(A+B)cosC + Cos(A+B)Sin C and expand the below ones . you will get the answer

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what is proof of 1) sin (A + B +C) = sinAcosBcosC + cosAsinBcosC + cosAcosBsinC - sinAsinBsinC

what is proof of
1) sin (A + B +C) = sinAcosBcosC + cosAsinBcosC + cosAcosBsinC - sinAsinBsinC

2 Answers

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