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Trigonometry question plz answer msnsjkslsndbbsjskaknsbsbdgdhjdnsbdvdhjdkkskhxbdbsjskoszpoaub
Tan2x=a/b,ie sec2x=a+b/b ,sec6x=(a+b)3/b3Similarly cosec6x=(a+b)3/a3,Sinxsec7x+cosxcosec7x=tanxsec6x+cotxcosec6x=(a+b)3.(a4+b4)/(a.b)7/2. As cot x =(b/a)1/2
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