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Grade: 11 
        
Trigonometry question plz answer msnsjkslsndbbsjskaknsbsbdgdhjdnsbdvdhjdkkskhxbdbsjskoszpoaub
9 months ago

Answers : (1)

Aman
13 Points 
							
Tan2x=a/b,ie sec2x=a+b/b ,sec6x=(a+b)3/b3
Similarly cosec6x=(a+b)3/a3,
Sinxsec7x+cosxcosec7x=tanxsec6x+cotxcosec6x
=(a+b)3.(a4+b4)/(a.b)7/2.       As cot x =(b/a)1/2
9 months ago
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  • Study Planner
  • NCERT Solutions
  • Discussion Forum
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